Resistance of a given wire of length „l‟ is 4ohms. The wire is stretched uniformly such that its length
becomes 3 l . Find the new resistance of the stretched wire.
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Answer:
hey mate here is ur ans
Explanation:
R= rho l/A where rho is density
4= rho l/A------>1
if length become 3l
Rn = rho 3l/A = 3 (rho l/A) where Rn is new resistance
from eq 1 we get rho l/A = 4
Rn= 3×4 = 12
Rn = 12
hope it help u
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