Resistance of a meatel wire of length 1 m is 26 ohm at 20 celcius . If the diameter of the wire is 0.3mm , what will be the resistivity of the meatel at that temperature? Using table 12.2, predict the material of the wire
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heya....
Resistance , R = 26Ω
Length of wire , L = 1m
diameter of circular part of wire ,d = 0.3mm = 0.3 × 10⁻³m
so, base area of wire , A = πr² = πd²/4 [ ∵d = 2r]
= 3.14 × (0.3 × 10⁻³)²/4m²
= 3.14 × 9 × 10⁻⁸/4 m²
= 28.26/4 × 10⁻⁸ m² = 7.06 × 10⁻⁸ m²
Now, use formula,
R = ρL/A
Here, R is the resistance, ρ is the resistivity , L is the length of wire and A is the base area of it .
So , ρ = RA/L = 26Ω × 7.06 × 10⁻⁸m²/1m
ρ = 1.8356 × 10⁻⁶ Ωm
Hence, resistivity is 1.8356 × 10⁻⁶ Ωm at 20°C
tysm.......@gozmit
Resistance , R = 26Ω
Length of wire , L = 1m
diameter of circular part of wire ,d = 0.3mm = 0.3 × 10⁻³m
so, base area of wire , A = πr² = πd²/4 [ ∵d = 2r]
= 3.14 × (0.3 × 10⁻³)²/4m²
= 3.14 × 9 × 10⁻⁸/4 m²
= 28.26/4 × 10⁻⁸ m² = 7.06 × 10⁻⁸ m²
Now, use formula,
R = ρL/A
Here, R is the resistance, ρ is the resistivity , L is the length of wire and A is the base area of it .
So , ρ = RA/L = 26Ω × 7.06 × 10⁻⁸m²/1m
ρ = 1.8356 × 10⁻⁶ Ωm
Hence, resistivity is 1.8356 × 10⁻⁶ Ωm at 20°C
tysm.......@gozmit
Answered by
4
solution
we know that.
resistive = AR/ l
Now, area of wire= 1m* 0.3mm
= 1000*0.3
= 300 mm^2
now,, putting value in formula.
=> resistivity= 300* 26/1000
= 26*3/ 10
= 7.8 ohm - mm
____________
hope it helps you. ☺☺
we know that.
resistive = AR/ l
Now, area of wire= 1m* 0.3mm
= 1000*0.3
= 300 mm^2
now,, putting value in formula.
=> resistivity= 300* 26/1000
= 26*3/ 10
= 7.8 ohm - mm
____________
hope it helps you. ☺☺
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