resistance of a metal wire of length 5 M is 100 ohm if the area of cross section of the wire is 3 into 10 raise to minus 7 M equal calculate the resistivity of the metal
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Resistance (R) = 50 Ω
Length of the wire ( l ) = 2 m
Diameter of the wire = 0.6 mm
Radius = 0.6 / 2 = 0.3 mm
= 3 × 10^-4 m
Resistivity ( ρ ) = ?
Area of cross sectional area of wire (A) = πr^2
= 3.14 ×( 3 × 10^-4)^2
= 2.826 × 10^9 m^2
We know,
ρ = RA / l
ρ = 50 × 2.826 × 10^-9 / 2
ρ = 25 × 2.826 × 10^-9
ρ = 70.65 × 10^-9 or 7.065 × 10^-8 Ω m
Resistivity of the wire is 7.065 × 10^-8 Ω m.
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Length of the wire ( l ) = 2 m
Diameter of the wire = 0.6 mm
Radius = 0.6 / 2 = 0.3 mm
= 3 × 10^-4 m
Resistivity ( ρ ) = ?
Area of cross sectional area of wire (A) = πr^2
= 3.14 ×( 3 × 10^-4)^2
= 2.826 × 10^9 m^2
We know,
ρ = RA / l
ρ = 50 × 2.826 × 10^-9 / 2
ρ = 25 × 2.826 × 10^-9
ρ = 70.65 × 10^-9 or 7.065 × 10^-8 Ω m
Resistivity of the wire is 7.065 × 10^-8 Ω m.
Read more on Brainly.in - https://brainly.in/question/3589015#readmore
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Apply the formula : Resistivity = ( Resistance × area )/ length
Ans: 6× 10^-6 ohm/m
swaritrathore:
Can u pls just tell me the final answer
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