Science, asked by flashmind, 1 year ago

resistance R1 R2 R3 and R4 connected as shown in the figure S1 and S2 R2 key discuss the current flowing in the circuit in the following case

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Answers

Answered by sathunandhu2003
45

The answer is given below.

Hpoe this helps

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Answered by moolchandnangaliya86
2

Answer:

Solution

The equivalent resistance of the series connection is:

R

eq

=R+R+R+R=4Rohm

Total current in the circuit ,

I=V/R=12/4R=3/R

Reading of voltmeter A = Voltage across R

1

=I×R

1

=3/R×R=3V

Reading of voltmeter B = Voltage across R

2

=I×R

2

=3/R×R=3V

Reading of voltmeter C = Voltage across the series combination of R

3

and R

4

=I×(R

3

+R

4

)=3/R×2R=6V

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