Resistence of rod is 1 ohm . It is bent in the form of square. What is resistance across adjoining corners?
Answers
answer : option (C) 3/16 Ω
it is given that,
resistance of a rod is 1Ω and it is bent in the form of square. we have to find the resistance across adjoining corners.
let length of rod is l,
when it is bent in the form of square.
perimeter of square = length of rod
⇒4 × side length of square = l
⇒side length = l/4
from formula, R = ρl/A
we know, resistance is directly proportional to length of wire when its cross sectional area remains constant.
R1/R2 = l1/l2
1Ω/R2 = l/(l/4)
R2 = 1/4 Ω
so, resistance of side length = 1/4 Ω
now see the figure,
three sides of square are in series combination.
so, R = 1/4 Ω + 1/4 Ω + 1/4 Ω = 3/4 Ω
now, R is joined in parallel with AB side of square .
so, Equivalent resistance , Req = (1/4)(3/4)/(1/4 + 3/4) = 3/16 Ω
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Answer:
can you pls tell me from which book that question is from?
Explanation: