Question

Resolve a weight of 10N in two directions which are parallel and perpendicular to a slape inclined at 30^(@) to the horizontal.

Answer 1

The weight parallel and perpendicular to the slope is:

• Given Weight, W =10 N and Θ =30°
• To calculate the weight parallel and perpendicular to slope, we have to resolve the vector in two perpendicular axes.

• Weight parallel to the slope = W sin Θ = 10 * sin 30° = 5 N

• Weight perpendicular to the slope = W cos Θ = 10 * cos 30° = 5√3 N