Question

Resolve in to factors
8 - (a-b)ki power 3
Pleaseee Answer!​

Answer 1

QN> 8 - (a-b) factorise

=> (2)^3 - (a-b)^3

applying a^3-b^3 = (2-(a-b)] {(2)^2+2(a-b)+(a-b)^2}

answer= [2-a+b][4+2a-2b+a^2+b^2-2ab]

Answer 2

Step-by-step explanation:

that that will be your answer