Question

Resolve into factors: 16a^2 - 4b^2 + 12bc - 9c^2

Answer 1

Factorising,

$16 {a}^{2} - 4 {b}^{2} + 12bc \: - 9 {c}^{2}$

$16 {a }^{2} - ( \: 4{b}^{2} - 12bc \: + \: 9 {c}^{2})$

$16 {a}^{2} - \: (2b \: - \: 3c \: )^{2}$

$(4a \: + \: 2b \: - \: 3c \: )(4 a \: - 2b \: + 3c)$