Question

resolve it to factor​

Answer 1

Answer:

1) (x+y)²-z²

= (x+y+z)(x+y-z)

2) (x-y)²-z²

= (x-y+z)(x-y-z)

3)(a+2b)²-c²

= (a+2b+c)(a+2b-c)

4)(a+3c)²-1²

= (a+3c+1)(a+3c-1)

Here ,

we used algebraic identity:

x²-y² = (x+y)(x-y)

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Answer 2

factor of the following question.

Step-by-step explanation:

Given:

1. (x + y)²- z²

2. (x - y)²- z²

3. (a + 2b)² - c²

4. (a + 3c)² - 1

Find:

Factor.

Computation:

We, know that

a² - b² = (a +b)(a - b)

1. (x + y)²- z²

(x + y + z)(x + y - z)

2. (x - y)²- z²

(x - y + z)(x - y - z)

3. (a + 2b)² - c²

(a + 2b +c)(a + 2b -c)

4. (a + 3c)² - 1

(a + 3c + 1)(a + 3c - 1)

Learn more:

https://brainly.in/question/11958007