resolve the following into factors : 4y² - 2y + 1/4
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We know 4y
2
−2y+1 =(2y)
2
−2(2y)(1)+(1)
2
We know appropriate identities x
2
−2xy+y
2
=(x−y)
2
Here x=2y and y=1, then
4y
2
−4y+1= (2y−1)
2
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Answer:
Step-by-step explanation:
4y² - 2y + 1/4=0
Multiplying both the sides of the equation by 4,
16y² -8y +1 =0
16y² - 4y -4y +1=0
4y(4y-1) -1(4y-1) =0
(4y-1) (4y-1) =0
Therefore,
4y-1=0
y=1/4
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