Question

RESOLVER LAS SIGUIENTES OPERACIONES CON NÚMEROS REALES:
((1/3) √0.81+(-1/2)^2)/(20/11)^(-1)

[7/4-(3/2* 6/4)]^2- 1/9


1/24+√7 -3 +1,4 -8 =

Answer 1

Question

RESOLVER LAS SIGUIENTES OPERACIONES CON NÚMEROS REALES:

((1/3) √0.81+(-1/2)^2)/(20/11)^(-1)

[7/4-(3/2* 6/4)]^2- 1/9

1/24+√7 -3 +1,4 -8 =

Answer

To verify : A×(B∩C)=(A×B)∩(A×C)

We have B∩C={1,2,3,4}∩{5,6}=ϕ

∴ L.H.S = A×(B∩C)=A×ϕ=ϕ

A×B={(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4)}

A×C={(1,5),(1,6),(2,5),(2,6)}

∴R.H.S.=(A×B)∩(A×C)=ϕ

∴L.H.S=R.H.S

Hence A×(B∩C)=(A×B)∩(A×C)