Resonance tube one end closed will resonate at what frequency
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At the frequency of one : threes not the ratio one: three
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frequencies, given by
f=nv2L
f=nv2L
where nn is a positive integer, LL is the length of the tube, and vv is the speed of sound in air. The fundamental frequency, which generally contains the most energy, is the case when n=1n=1, i.e.
f0=v2L.
f0=v2L.
The wavelengths involved with each of the resonant frequencies are related to the frequencies by
λ=vf,
λ=vf,
i.e.,
λ=2Ln.
λ=2Ln.
This means that at the fundamental frequency, L=λ/2L=λ/2, as per your understanding that the tube is a half-wavelength long.
f=nv2L
f=nv2L
where nn is a positive integer, LL is the length of the tube, and vv is the speed of sound in air. The fundamental frequency, which generally contains the most energy, is the case when n=1n=1, i.e.
f0=v2L.
f0=v2L.
The wavelengths involved with each of the resonant frequencies are related to the frequencies by
λ=vf,
λ=vf,
i.e.,
λ=2Ln.
λ=2Ln.
This means that at the fundamental frequency, L=λ/2L=λ/2, as per your understanding that the tube is a half-wavelength long.
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