Question

respecut)
1
9. Find the GP whose 4th and 7th terms are
.
486 respectively
18 and​

Answer 1

Answer:

required gp

13122, 4374, 1458 and so on

Step-by-step explanation:

4th and 7th terms are 486 respectively 18

4th term a r^3= 486-----> 1

7 th term = a r^6= 18------>2

equation 1 ÷ equation 2

$\frac{a {r}^{3} }{a {r}^{6} } = \frac{486}{18}$

$\frac{1}{ {r}^{3} } = 27 = {3}^{3}$

r= 1/3

from 1

$a \times {r}^{3} = \frac{a}{27 } = 486$

a= 13122

ar= 13122/3= 4374

ar^2= 4374/3= 1458

required gp

required gp13122, 4374, 1458 and so on