Math, asked by kit1917, 4 months ago

ress
in the figure given below, ABCD is a parallelogram. P and Q are points on the sides AB and CD respectively
such that PB = DQ. Prove that PQ and AC bisect each other.
0
А
P
B

Answers

Answered by itzAashish
6

Answer:

In triangles APO and OQC

∠OAP=∠OCQ ( taking Ac as transversal then angles are on opposites sides of transversal)

AP=CQ (given )

∠OPA=∠OQC ( taking PQ as transversal then angles are on opposites sides of transversal )

By ASA criterion of congruency triangle APO is congruent to triangle OQC .

PO=OQ ( byCPCT )

#HAVE A NICE DAY

Answered by Anonymous
2

Answer:

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