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in the figure given below, ABCD is a parallelogram. P and Q are points on the sides AB and CD respectively
such that PB = DQ. Prove that PQ and AC bisect each other.
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А
P
B
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In triangles APO and OQC
∠OAP=∠OCQ ( taking Ac as transversal then angles are on opposites sides of transversal)
AP=CQ (given )
∠OPA=∠OQC ( taking PQ as transversal then angles are on opposites sides of transversal )
By ASA criterion of congruency triangle APO is congruent to triangle OQC .
PO=OQ ( byCPCT )
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