Rest of consistance and solve system of equations. 2x+6y+11=0,6x+20y-63+3=0,6y-18z+1=0
Answers
Answered by
1
Answer:Given:
2x+6y+11=0
6x+20y−6z+3=0
6y−18z+1=0
Converting above equations in the determinant form, we get
Δ=
∣
∣
∣
∣
∣
∣
∣
∣
2
6
0
6
20
6
0
−6
−18
∣
∣
∣
∣
∣
∣
∣
∣
Here, Δ=−648+648=0
Now,
Δ
1
=
∣
∣
∣
∣
∣
∣
∣
∣
−11
−3
−1
6
20
6
0
−6
−18
∣
∣
∣
∣
∣
∣
∣
∣
Δ
1
=3276
=0
Δ
2
=
∣
∣
∣
∣
∣
∣
∣
∣
2
6
0
−11
−3
−1
0
6
−18
∣
∣
∣
∣
∣
∣
∣
∣
Δ
2
=−1092
=0
And Δ
3
=
∣
∣
∣
∣
∣
∣
∣
∣
2
6
0
6
20
6
−11
−3
−1
∣
∣
∣
∣
∣
∣
∣
∣
Δ
3
=−364
=0
So, here D=0 and no-one among D
1
,D
2
,D
3
is 0.
Hence, the system is inconsistent
Hence, option C.
Step-by-step explanation:
Similar questions