Question

Retardation produced, due to brakes, in moving train is 0.5 m/s². Train stops after 40s after application of brakes. If train is to stop in a certain place on platform, what would be the distance from plathform, of a place where brakes are appplied ?

GSEB - Class 9 Chapter - 1.Motion Page 16

Answer 1

Answer:

Retardation = change in velocity /time taken

0.5 = change in velocity /40

change in velocity = 20m/s

Since train stops final velocity (v) = 0

Let u be initial velocity

20 = u-v

u = 20

s =UT +1/2 at^2

(20)(40)+1/2(-0.5)(40)(40)

800-400

s = 400m

Hope this helps you