Math, asked by shaiksalam37, 19 days ago

Reversing the digits of ishans age give his father age.The father's age is 4.5 times the ishans age what is the father's age?

Answers

Answered by payalrajwaniya2005
1

Answer:

37

Step-by-step explanation:

Let fathers age = 10x + y

Sons age = 10y + x (As, it is got by reversing digits of fathers age)

At that point

(10x + y) - 1 = 2{(10y + x) - 1}

=> x = (19y - 1)/8

Let y = 3 then x = 7.

For any other y value, x value combined with y value doesnt give a realistic age (like fathers age 120 etc)

So, this has to be solution.Hence fathers age = 73.

Sons age = 37.

Answered by shivaganeshsoori
2

Answer:

fathers age = 73

Step-by-step explanation:

Let fathers age = 10x + y

Sons age = 10y + x (As, it is got by reversing digits of fathers age)

At that point

(10x + y) - 1 = 2{(10y + x) - 1}

=> x = (19y - 1)/8

Let y = 3 then x = 7.

For any other y value, x value combined with y value doesnt give a realistic age (like fathers age 120 etc)

So, this has to be solution.Hence fathers age = 73.

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