Math, asked by anilbayyavarapu9, 1 month ago

Revisit The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then what is the value of X"?​

Answers

Answered by tsalikiindira
1

Answer:

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Answered by tennetiraj86
4

Step-by-step explanation:

Given :-

The cost price of 20 articles is the same as the selling price of x articles. The profit is 25%

To find :-

What is the value of "X"?

Solution :-

Method-1:-

Let the cost price of 20 articles be Y

The cost price of 1 article = Y /20

Selling Price of X articles = Cost Price of 20 articles = Y

Selling Price of one article = Y/X

Profit on them = 25%

Profit = SP-CP

=> P = (Y/X)-(Y/20)

=> P = (20Y-XY)/(20X )

We know that

P% = (Profit /CP) ×100

=> 25 = [{(20Y-XY)/(20X)}/(Y/20)]×100

=> 25/100 = [(20Y-XY)/(20X)]×(20/Y)

=> 1/4 =[ (20-X)Y/(20X)]×(20/Y)

=> 1/4 = (20-X)/X

=> X = 4(20-X)

=> X = 80-4X

=> X+4X = 80

=> 5X = 80

=> X = 80/5

=> X = 16

Therefore, X = 16

Method -2:-

We know that

If CP of M articles is equal to N articles then P% =[ (M-N)/N ]×100

=> [(20-X)/X ]×100 = 25

=> (20-X)/X = 25/100

=> (20-X)/X = 1/4

=> 4(20-X) = X

=> 80-4X = X

=> X+4X = 80

=> 5X = 80

=> X = 80/5

=> X = 16

Answer:-

The value of X for the given problem is 16

Used formulae:-

→ Profit = SP-CP

→ P% = (Profit /CP) ×100

  • CP = Cost Price
  • SP = Selling Price
  • P% = Profit Percentage

→If CP of M articles is equal to N articles then P% =[ (M-N)/N ]×100

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