Question

REVISITING IRRATIONAL NUMBER √2 is irrational nu2 is irrational number
let
assume that √2 is irrational

√2=a/b
squaring both sides
2=a2/b2
2b²=a²
b²=a/2
a² is divisible by 2 and
also a is divisible by 2
put
a=2c
a=2c
2b²=(2c)²
2b²=4c²
b²=4c²/2
b²=2c²
b²=b²/2
​

Answer 1

Step-by-step explanation:

2=a/b

squaring both sides

2=a2/b2

2b²=a²

b²=a/2

a² is divisible by 2 and

also a is divisible by 2

put

a=2c

a=2c

2b²=(2c)²

2b²=4c²

b²=4c²/2

b²=2c²

b²=b²/2