rhe numerator of a rational number is 3 less than its denomirator if the numerator increasedby 1 and the denomaratoris increased by 3 the number becomes 1/2 find the rational number
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let the denominator be x
so numerator will be x-3
A/Q. x-3+1/x-3=1/2
x-4/1-3=1/2
2(x-4)=1-3
2x-4=2
2x=6
x=3
so numeret =3-3
=0
denominator =3
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so numerator will be x-3
A/Q. x-3+1/x-3=1/2
x-4/1-3=1/2
2(x-4)=1-3
2x-4=2
2x=6
x=3
so numeret =3-3
=0
denominator =3
if it helpful plz mark brainlist and follow me
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