Question

∆ rhp~ ∆ ned in ∆ ned ne = 7 cm angle d = 30° , angle n = 20 ° and hp : ed = 4:5 draw figure video step by step shala .com​

Answer 1

Steps of Construction:

1. Draw a line segment PM = 5.4 cm.

2. Draw ∠MPX=60°∠MPX=60°.

3. Draw another angle ∠PMY=70°∠PMY=70°. The rays PX and MY intersects at point T.

4. Then Δ∆PMT is the required triangle.

5. Draw perpendicular bisectors of sides PM and PT (any two sides) which intersect at O.

6. Taking OP or OM or OT as the radius, draw the required circumcircle.

Construct the circumcircle of △△SIM in which SI = 6.5 cm, ∠∠I = 125°° and IM = 4.4

Steps of construction:

1. Draw a line segment IM = 4.4 cm.

2. Draw ∠MIX=125°∠MIX=125°.

3. With I as the centre and a radius of 6.5 cm, draw an arc cutting IX at S.

4. Join SM.

5. Then △△SIM is the required triangle.

6. Draw the perpendicular 

IM (any two sides) which intersect at O.

7. Taking OS or OI or OM as the radius, draw the required circumcircle.