Math, asked by chips4475, 1 year ago

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Answered by siddhartharao77
5
 Given : \frac{1}{6} - 8 \sqrt[3]{ \frac{1}{64} }

 \frac{1}{6} - 8 *  \frac{1}{4}

 \frac{1}{6} - 2

 \frac{-2 * 6 + 1}{6}

 \frac{-11}{6}


Hope this helps!

siddhartharao77: :-)
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Answered by Anonymous
4
Hi,

Please see the attached file !


Thanks
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