Math, asked by vikram14340, 3 months ago

right hand limit of a function at the point x mentioned against them in check with their function have limits source point f(x)=x/2 if x<2. x^/3 if x>2. a=2​

Answers

Answered by avika4214
0

Step-by-step explanation:

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Answered by pranayasahu
0

Step-by-step explanation:

right hand limit of a function at the point x mentioned against them in check with their function have limits source point f(x)=x/2 if x<2. x^/3 if x>2. a=2

Left hand limit:

x→1

lt

f(x)

=

x→1

lt

1+x

2

[∵f(x)=1+x

2

when x≤1]

=1+1

=2

Right hand limit

x→1

+

lt

f(x)

=

x→1

lt

2−x [∵f(x)=2−x when x>1]

=1

Since,

x→1

lt

f(x)

=

x→1

+

lt

f(x),

x→1

lt

f(x) does not exist.

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