CBSE BOARD X, asked by SHASWATIH1986, 8 months ago

Right triangle angle C=90 Tan B =√3 Tan A= 1/3 then show Sin A ,Cos B+ CosA Sin B=1

Answers

Answered by yashika9982yashu46
0

Explanation:

tanA=BC/AB=1 / root 3

this BC = 1 AB = root 3

In triangle ABC ,

AB2+BC2= AC2

Thus AC=2(BY PYTHAGORAS THEORM)

SinAcosC+ cosAsinC=1/2*1/2+root 3/2*root3/2

=1/4+3/4

=4/4

=1

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Answered by neetimadaan1411
0

Answer:

i hope it helps

Explanation:

tanA=BC/AB=1 / root 3

this BC = 1 AB = root 3

In triangle ABC ,

AB2+BC2= AC2

Thus AC=2(BY PYTHAGORAS THEORM)

SinAcosC+ cosAsinC=1/2*1/2+root 3/2*root3/2

=1/4+3/4

=4/4

=1

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