Right triangle angle C=90 Tan B =√3 Tan A= 1/3 then show Sin A ,Cos B+ CosA Sin B=1
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Explanation:
tanA=BC/AB=1 / root 3
this BC = 1 AB = root 3
In triangle ABC ,
AB2+BC2= AC2
Thus AC=2(BY PYTHAGORAS THEORM)
SinAcosC+ cosAsinC=1/2*1/2+root 3/2*root3/2
=1/4+3/4
=4/4
=1
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Answer:
i hope it helps
Explanation:
tanA=BC/AB=1 / root 3
this BC = 1 AB = root 3
In triangle ABC ,
AB2+BC2= AC2
Thus AC=2(BY PYTHAGORAS THEORM)
SinAcosC+ cosAsinC=1/2*1/2+root 3/2*root3/2
=1/4+3/4
=4/4
=1
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