Question

Right triangle LMN has vertices L(7, –3), M(7, –8), and
N(10, –8). The triangle is translated on the coordinate plane so the coordinates of L’ are (–1, 8).

Which rule was used to translate the image?

(x, y) → (x + 6, y – 5)
(x, y) → (x – 6, y + 5)
(x, y) → (x + 8, y – 11)
(x, y) → (x – 8, y + 11)

Answer 1

Answer:  

(x, y) → (x – 8, y + 11) rule was used to translate the image.

Explanation:

Given:

Right angle LMN has vertices  L(7, –3), M(7, –8), and N(10,-8).

The triangle is now translated on the coordinate plane so the coordinates of   $L{}'$  are (-1,8).

The only rule was used to translate the vertices  

L(7, –3) to $L{}'(-1,8)$  is, $(x,y)\rightarrow(x-8, y+11)$

Check the transformation that apply:

(x, y) → (x – 8, y + 11)

$L(7,-3) \rightarrow L{}'(7-8, -3+11)$

$L(7,-3) \rightarrow L{}'(-1, 8)$

Therefore, the rule which was used is $(x, y) \rightarrow (x-8, y + 11)$.

Answer 2

Answer: D

Step-by-step explanation: