Question

ring of radius R with charge Q uniformly distributed over it is rotated with angular speed Omega around its Axis find magnetic moment of the Ring​

Answer 1

Answer: magnetic moment m = iA

Where i - current in the loop

A - Area of the loop.

Here the current i = Q/T = Qw/2pi

Area = pi*R^2

Using those, m = (QwR^2)/2