Math, asked by luckypal45516, 5 months ago

Rinku invested 100000 in a company at 13% pa. compounded annually. Find
(1) the amount credited in his account at the end of 2 years.
(ii) the interest he got in the 3rd year​

Answers

Answered by MuzammilHasanNaqvi
4

Step-by-step explanation:

For first year:

Principal= Rs. 100000

Rate=13% p.a.

Time=1 year

Interest=P×R×T/100

=100000×13×1/100

=Rs 13000

Amount at the end of first year=Principal+Interest

=100000+13000

=Rs 113000

For second year:

Principal=113000 (Amount of the first year)

Rate=13% p.a.

Time=1 year

Interest=P×R×T/100

=113000×13×1/100

=Rs. 14690

Amount at the end of second year=113000+14690

=127690

For third year:

Principal=127690

Rate=13%

Time=1 year

Interest= 127690×13×1/100

=Rs. 16599.7

  1. Amount credited in Rinku's account at the end of 2 years= Rs. 127690
  2. Interest he got in the third year=16599.7

Answered by Anonymous
5

Question:-

Rinku invested 100000 in a company at 13% pa. compounded annually. Find

(1) the amount credited in his account at the end of 2 years.

(ii) the interest he got in the 3rd year

Find:-

Rinku invested in a company at 13% pa. = 100000

the amount credited in his account at the end of 2 years.= 200000

2 years = 200000

4% p.a = 2163.20

then,

13% = ?

Find out:+

4%= 2163.20

2163.20×3 =

= 6489.90 \: ans=6489.90ans

Given:-

In how many years will Rs 2000 amount to Rs 2163.20 at 4% p.a compounded annually

Amount:-

13% p.a= 6489 . 90 Amount.

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