Question

solve the problem???​

Answer 1

Answer:

1,3,5,....,(2n−1)

A.M=

number of terms

sum of all terms

1+3+5+.....+(2n−1)=

2

n

[1

st

term + last term]

=

2

n

[1+2n−1]=

2

2n

2

=n

2

A.M=

n

n

2

=n