Rishabh, a 20 kg child on his bicycle moving with a speed of 10ms-1 takes turn on a circular turning of radius 100cm. what is the centripetal force acting on Rishabh 1 point
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2,000 N since we hve asked about centripetel force
Step-by-step explanation:
M=20kg
V=1 m
V= 10m/s
so Centripetal force equals
mv²/r
(20)× (10)²/ 1= 2,000 N
PLZ MARK ME AS BRAINLIEST QUESTION
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