Rita and Sneha are born in the year 1992 what is the probability that they have same birthday?
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1992 was not a leap year, so there were 365 days in the year. Let’s assume that these two people are independent and uniform distribution on births by days of the year. If you told me that they were twins, then the probability is near 1 on the same day (could have one born prior to midnight and the other afterwards). Anyway, with independence and uniform distribution (and no time zone complications), the probability that two people are born on a particular day of 1992 is:
P(both born on a particular day of 1992) = (1/365)*(1/365)
Since there are 365 days, the probability of any day is:
P(both born on same day in 1992) = 365*(1/365)*(1/365) = 1/365
Thus, probability of different birthdays = 1 - (1/365) = 364/365
P(both born on a particular day of 1992) = (1/365)*(1/365)
Since there are 365 days, the probability of any day is:
P(both born on same day in 1992) = 365*(1/365)*(1/365) = 1/365
Thus, probability of different birthdays = 1 - (1/365) = 364/365
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They may or may not have same Birthday.
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