Riti has a box of sweets. She distributes 20%of the sweets.Pooja comes and distributes 15%of the remaining sweets.If a total of 80 sweets were distributed, find how many sweets were there in the box?
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Let the number of sweets be 'x'.
Let the 2525 children be given ′y′′y′ sweets each.
Let the2828 children be given ′z′′z′ sweets each.
This implies,x=25y+8x=25y+8
x=28z+22x=28z+22
y,zy,z belong to Natural numbers.
This also implies y>zy>z.
And, 14∗(2z+1)=25y14∗(2z+1)=25y
This is possible if y=14y=14 and 2z+1=252z+1=25
Therefore, y=14,z=12y=14,z=12
So, the total no. of sweets is 358358.
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