Question

the perimeter of a right triangle is 24m. its hypotenuse is 10m. the area of the triangle is​

Answer 1

Step-by-step explanation

Let the side be a and b

sum of all side =perimeter

a+b+h=24

a+b+14=24

a+b=14

a=14-b

Now apply Pythagor theorem

(h)^2=(a)^2+(b)^2

(10)^2=(14-b)^2+(b)^2

100=196+b^2-28b+b^2

-96=2b^2-28b

2b^2-28b+96=0

2b^2-16b-12b+96

2b(b-8)-12(b-8)

(2b-12)(b-8)

b=6,,b=8

Now we take b=8then

a=14-8

a=6

area of triangle=1/2×b×h

1/2×6×10

1/2×60

30m^2....is ryt answer

Hpoe it will help u

Answer 2

Given: Perimeter of triangle is 24 m

hypotenuse is 10 m .

To find: area of triangle ?

Solution:

Let hypotenuse is a

base =b

perpendicular= c

perimeter of triangle is a+b+c

put value of a, we get

10+ b+c=24

b+c=14

b =14 - c

apply PGT in right angle triangle

a square= b square+ c square

100+ 2cb= 196

2cb =96

cb =48

area of triangle = 1/2 ×base × height

= 1/2× 48

= 28

area of triangle= 28 sq m

Oh it takes more time to solve.

sorry for that ...

hope this will help you...