Question

Ritu's mother is 30 years older than her. Ten years ago she was thrice old of Ritu . Find their present ages.​

Answer 1

Step-by-step explanation:

Let, Ritu’s daughter age two years ago be x and Ritu’s age be 3x.

Ritu’s age 2 year hence = 3x + 2 + 2 = 3x + 4

Ritu’s daughter age 2 year hence = x + 2 + 2 = x + 4

Given that,

⇒ 5(x + 4) = 2 × (3x + 4)

⇒ 5x + 20 = 6x + 8

⇒ 12 = x

∴ The sum of the present ages of Ritu and her daughter = (x + 2) + (3x + 2) = 4x + 4 = 4 × 12 + 4 = 52 years.

Answer 2

Answer:

Ritu's age is 25 and her mother's age is 55.

Step-by-step explanation:

Let Ritu's age be x and her mother's age y.

In present situation, given,

y = x + 30

x - y = -30 .... (1)

Ten years ago,

y - 10 = 3(x - 10)

3x - y = 20 .... (2)

Subtracting (1) from (2)

2x = 50

x = 25

Therefore,

y = 55