Question

rms speed of hydrogen molecule at 27°c

Answer 1

Hi buddy

Here is your answer

☑️ The root mean square velocity of hydrogen molecule at 27oC is υH and that of oxygen at 402oC is υO, then.☑️

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#sibi ❤️

Answer 2

Answer:

Explanation:

RMS = sqrt (3)(R)(T)/(M)

R = ideal gas constant = 8.3145 (kg·m2/sec2)/K·mol

T = absolute temperature in Kelvin

M = mass of a mole of the gas in kilograms.

RMS = sqrt (3)(8.314)(300)/0.032 = sqrt 239.4

RMS = 15.5 m/s