Question

Rocket-powered sleds are used to test the human response to acceleration. If a rocket-powered sled is accelerated to a speed of 444 m/s in 1.83 seconds, then what is the acceleration and what is the distance that the sled travels?

Answer 1

v=444m/s
u=0m/s
v=u + at
444=0 + a*1.83
a=242.623
s=ut + 1/2*at^2
s=406.26m

Answer 2

The acceleration and distance traveled by the sled are a=243m/s² and d = 406m.

Given:

Initial velocity, $u=0m/s$

Final velocity, $v=444m/s$

Time, $t=1.83s$

To Find:

Acceleration and distance of sled.

Solution:

Let, $a$ be the acceleration.

here, by using $v=u+at$

we get,

$444=0+a(1.83)\\a=444/1.83m/s^{2} \\a=243m/s^{2}$

here we get  acceleration,$a=243m/s^{2}$

now, if $d$ will be the traveled distance by sled, then

by using,

$v^{2} -u^{2} =2aS$

now, after putting the value on the above formula.

we get,

$444^{2}-0^{2}=2(243)d\\ d=406m$

Hence, the acceleration and distance traveled by the sled are a=243m/s² and d = 406m.