Question

Rohan a juice seller has set up the juice shop . He has two types of glass in the shapes of a frustum of a cone whose inner diameter of the bottom of a frustum of cone is 10 cm and that of the top is 6 cm and height 5 cm . find (i)volume of both types of glass (ii)which has minimum capacity

Answer 1

Answer:

Step-by-step explanation:

Volume of frustum of cone = Π h /3 ( r1² + r2² + r1 x r2)

here h = 5 cm

r1 = 10/2 = 5 cm

r2 = 6/2 = 3 cm

Volume of frustum of cone = 22/7 x 5 / 3 x ( 5² + 3² + 15)

Volume of frustum of cone = 22/7 x 5 / 3 x 49

Volume of 1st glass  = 256.67 cm³

Assuming Second Glass has following parameters :- inner diameter of the bottom of a frustum of cone is 14 cm and that of the top is 4 cm and height 4 cm

Volume of frustum of cone = Π h /3 ( r1² + r2² + r1 x r2)

here h = 4 cm

r1 = 14/2 = 7 cm

r2 = 4/2 = 2 cm

Volume of frustum of cone = 22/7 x 4 / 3 x ( 7² + 2² + 14)

Volume of 2nd glass  = 280.76 cm³

Glass 1 has less capacity.