Question

Rohan buys 12 computers and 12 printers.If the cost of one computer and one printer is Rs.56,233 and Rs.7,867 respectively, find the total cost incurred by Rohan.(Use distributive property of multiplication)​

Answer 1

$\huge\mathbb\red{QUESTION:-}$

Rohan buys 12 computers and 12 printers.If the cost of one computer and one printer is Rs.56,233 and Rs.7,867 respectively, find the total cost incurred by Rohan.(Use distributive property of multiplication)

$\huge\mathbb\red{SOLUTION:-}$

Cost of one computer =Rs.56,233

Cost of one printer=Rs.7,867

___________________________________

Cost of 12 computer =

12×(56000+200+30+3)

=Rs.6,74,796

___________________________________

Cost of 12 printers =12×(7000+800+60+7)

=Rs.94,404

___________________________________

Cost of 12 printers=Rs.094404

Cost of 12 computer=Rs.674796

Total cost is =(094404+674796)

= Rs. 7,69,200

____________________________________

$\Large\boxed{</strong><strong>Solved</strong><strong>}$

#Be_Brainly.✔✔

Answer 2

Step-by-step explanation:

the cost of 1 computer is 56233

the cost of such 12 computer=12×56233

=674796

the cost of 1 printer is 7867

the cost of such 12 printers=12×7867

=94404

total cost incurred by Rohan=674796+94404

=769200