Rohan buys 12 computers and 12 printers, the cost of one computer and one
printer is 56,233 and 7,867 respectively, find the total cost incurred by Rohan
(Use distributive property of multiplication)
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Answer:
The total cost incurred was ₹769200
Step-by-step explanation:
No. of computers = 12
Cost of one computer = ₹56233
No. of printers = 12
Cost of one printer = ₹7867
Cost of all computers = 12 x ₹56233
Cost of all printers = 12 x ₹7867
Total cost incurred = (12 x ₹56233) + (12 x ₹7867)
= 12 (₹56233 + ₹7867) (as per distributive property)
= 12 x ₹64100
= ₹769200
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