Rohan deposited 25000 in two accounts. He
deposited some amount in saving account at
simple interest at 6% per annum and remaining
amount in fixed deposit at 12% per annum
simple interest. If he gets *5700 as total interest
after 2 years, then the amount he deposited in
fixed deposit is
Answers
He deposited 2500 $ and 22500$ respectively.
Step-by-step explanation:
Part I 6.00% per annum ------------- Amount invested =x
Part II 12.00% per annum ------------ Amount invested = y =
Total amount = 25000 Rs
Interest = 2850
Part I 6.00% per annum ---x
Part II 12.00% per annum ---y
Total investment
x + 1 y= 25000 -------------1
Interest on both investments
for one year interest is 2850
6.00% x + 12.00% y= 2850
Multiply by 100
6 x + 12 y= 285000.00 --------2
Multiply (1) by -6
We get
-6 x -6 y= -150000.00
Add this to (2)
0 x 6 y= 135000
divide by 6
y = 22500
- Part I 6.00% 2500 $
- Part II 12.00% 22500$
Thus he deposited 2500 $ and 22500$ respectively.
Answer:
He deposited 2500
$ and 22500$ respectively.
Step-by-step explanation:
Part I 6.00% per annum ------------- Amount invested =x
Part II 12.00% per annum ------------ Amount invested = y =
Total amount = 25000 Rs
Interest = 2850
Part I 6.00% per annum ---x
Part II 12.00% per annum ---y
Total investment
x + 1 y= 25000 -------------1
Interest on both investments
for one year interest is 2850
6.00% x + 12.00% y= 2850
Multiply by 100
6 x + 12 y= 285000.00 --------2
Multiply (1) by -6
We get
-6 x -6 y= -150000.00
Add this to (2)
0 x 6 y= 135000
divide by 6
y = 22500
Part I 6.00% 2500
$
Part II 12.00% 22500$
Thus he deposited 2500
$ and 22500$ respectively.
Step-by-step explanation:
Hope this answer will help you.✌️