Math, asked by biju2124, 10 months ago

Rohan deposited 25000 in two accounts. He
deposited some amount in saving account at
simple interest at 6% per annum and remaining
amount in fixed deposit at 12% per annum
simple interest. If he gets *5700 as total interest
after 2 years, then the amount he deposited in
fixed deposit is​

Answers

Answered by wajahatkincsem
4

He deposited 2500 $ and 22500$ respectively.

Step-by-step explanation:

Part I 6.00% per annum ------------- Amount invested =x

Part II 12.00% per annum ------------ Amount invested = y =

Total amount = 25000 Rs

Interest = 2850

Part I 6.00% per annum ---x

Part II 12.00% per annum ---y

Total investment

x + 1 y= 25000 -------------1

Interest on both investments

for one year interest is 2850

6.00% x + 12.00% y= 2850

Multiply by 100

6 x + 12 y= 285000.00 --------2

Multiply (1) by -6

We get

-6 x -6 y= -150000.00

Add this to (2)

0 x 6 y= 135000

divide by 6

y = 22500

  • Part I 6.00%  2500 $
  • Part II 12.00%  22500$

Thus he deposited 2500 $ and 22500$ respectively.

Answered by 2008shrishti
1

Answer:

He deposited 2500

$ and 22500$ respectively.

Step-by-step explanation:

Part I 6.00% per annum ------------- Amount invested =x

Part II 12.00% per annum ------------ Amount invested = y =

Total amount = 25000 Rs

Interest = 2850

Part I 6.00% per annum ---x

Part II 12.00% per annum ---y

Total investment

x + 1 y= 25000 -------------1

Interest on both investments

for one year interest is 2850

6.00% x + 12.00% y= 2850

Multiply by 100

6 x + 12 y= 285000.00 --------2

Multiply (1) by -6

We get

-6 x -6 y= -150000.00

Add this to (2)

0 x 6 y= 135000

divide by 6

y = 22500

Part I 6.00%  2500

$

Part II 12.00%  22500$

Thus he deposited 2500

$ and 22500$ respectively.

Step-by-step explanation:

Hope this answer will help you.✌️

Similar questions