Question

Rohan goes 10m due east and then 30m due north. find his distance from starting point

Answer 1

Rohan goes 10m east.

30m north.

By pythagoras theorem:

$distance^2=30^2+10^2$

$d^2=900+100$

$=d^2=1000$

$d=10\sqrt{10}$

He travelled this distance north east.

Thanks.

Answer 2

Let the distance between the starting and ending point be d.

Rohan goes 10m due east and then 30m due north

So by pythagoras theorem,

$d {}^{2} = 30 {}^{2} + 10 {}^{2}$
$= d {}^{2} = 900 + 100 = 1000$
[tex]d = \sqrt{1000} = 10 \sqrt {10}
Hope this helps :)