Rohan is now 9 years older than Raju.In ten years Rohan will be twice as old as Raju was 10 years ago. Find their present ages?
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Answered by
3
let raju's present age = x years
then rohan's present age =( x+9) years
10 years ago raju's age =( x-10) years
In 10 years rohan's age = x+9+10 = x+19
But as per sum:
x+19 = 2(x-10)
x+19 = 2x-20
2x-x = 20+19
x = 39
Therefore present age of raju = 39 years
present age of rohan = 48 years
then rohan's present age =( x+9) years
10 years ago raju's age =( x-10) years
In 10 years rohan's age = x+9+10 = x+19
But as per sum:
x+19 = 2(x-10)
x+19 = 2x-20
2x-x = 20+19
x = 39
Therefore present age of raju = 39 years
present age of rohan = 48 years
Answered by
4
Let the age of Raju be x years.
Then,
Age of Rohan = (x+9) years.
Now,
Age of Raju 10 years ago = (x-10)years.
After 10 years,
Rohan's age = (x+19) years.
But according to Question,
Rohan's age = 2(x-10).
Therefore,
⇒2(x-10)=x+19
⇒2x-20=x+19
⇒x=39
Therefore,
Age of Raju = 39 years.
Age of Rohan = 39+9 = 48 years. Ans.
HOPING THAT IT WILL HELP YOU!!!
Then,
Age of Rohan = (x+9) years.
Now,
Age of Raju 10 years ago = (x-10)years.
After 10 years,
Rohan's age = (x+19) years.
But according to Question,
Rohan's age = 2(x-10).
Therefore,
⇒2(x-10)=x+19
⇒2x-20=x+19
⇒x=39
Therefore,
Age of Raju = 39 years.
Age of Rohan = 39+9 = 48 years. Ans.
HOPING THAT IT WILL HELP YOU!!!
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