Question

Rohit and Vicky are playing a game both have a dice is both of them through their dice.
if the sum of the numbers we get on the two dice is more than 6 Rohit wins.
if the sum of the number de go get on the two dice is less than 6 vicky wins.
if the sum of the number de get on the two dice is equal to 6 no one wins
• in the game Rohit ko 3 on his dice but the given the game what could be the possible number Vicky got on the dice?
•whose probability of winning is more?​

Answer 1

ANSWER:

The probability of Vicky getting on the dice is $1,2,3,4,5$ or $6.$

The probability of who wins is Rohit.

Step-by-step explanation:

Given: Rohit and Vicky both play a game using dice.

            Various possibilities can be got using the dice.

To find What is the possible number that Vicky can get on the dice.

             Whose possibility is more of winning the game?

Solution:

• Possible outcomes if $2$ dice are thrown:

$(1,1) , (1,2), (1,3), (1,4), (1,5) , (1,6)\\(2,1), (2,2) , (2,3), (2,4) , (2,5), (2,6)\\(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)\\(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)\\(5,1), (5,2), (5,3), (5,4), (5,5), (6,5)\\(6,1), (6,2), (6,3), (6,4),(6,5),(6,6)$

• Total outcomes $= 36.$
• Outcomes with sum < $6=10$
• Outcomes with sum $=6=5$
• Outcomes with sum >$6=21$
• Probability of Rohit winning: $\frac{21}{36}$
• Probability of Vicky winning: $\frac{10}{36}$
• Therefore the probability of Rohit winning is greater.
• Possible numbers that Vicky got on dice can be: $1,2,3,4,5$ or $6$.

PROJECT CODE:  #SPJ1