rohit borrows rs 86000 from arun for two years at 5% simple interest .he immediately lends out his money to akshay at 5% compound interest compounded annually for the same period. Calculate rohit's profit in the transaction at the end of two years.
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Answered by
149
86,000 at 5% S.I for 2 years.
S.I = P*R*T/100 = 86000*5*2/100 = 8600 Rs.
86000 at 5% C.I for 2 years
C.I for 1st year = 86000*5*1/100 = 4300
A = P + C.I = 86000 + 4300 = 90,300
This becomes the P for 2nd year
90,300 at 5%
C.I for second year = 90300 * 5 * 1/100 = 4515
Total C.I = 4300 + 4515 = 8815 Rs.
Rohit has to pay Arun Rs.8600
But Rohit receives from Akshay Rs. 8815
Hence Rohit's profit = 8815 - 8600 = Rs. 215
Hope it helps.
S.I = P*R*T/100 = 86000*5*2/100 = 8600 Rs.
86000 at 5% C.I for 2 years
C.I for 1st year = 86000*5*1/100 = 4300
A = P + C.I = 86000 + 4300 = 90,300
This becomes the P for 2nd year
90,300 at 5%
C.I for second year = 90300 * 5 * 1/100 = 4515
Total C.I = 4300 + 4515 = 8815 Rs.
Rohit has to pay Arun Rs.8600
But Rohit receives from Akshay Rs. 8815
Hence Rohit's profit = 8815 - 8600 = Rs. 215
Hope it helps.
Answered by
105
Answer:215
Step-by-step explanation:
S.I.=p×r×t/100
=86000×2×5/100
=8600
For C.I.
Amount=p×(1+r/100)^2
=86000×(1+5/100)^2
=86000×21/20×21/20
=94815
C.I.=amount-p
=94815-86000
=8815
Since,rohit gets 8815 and returns 8600
Therefore, profit=8815-8600
=215
Hope it helps:-D
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