Rohit bought two scooters for rupees 18000 by selling one at a profit of 25% and the other at a loss of 20% in either gain nor loses find the cost price of each scooter
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Step-by-step explanation:
Let the C.P. of the 1
st
scooter = Rs. x.
Then, C.P. of the 2
nd
scooter = Rs. (18000−x)
S.P. of 1
st
scooter = Rs. x×
100
125
= Rs.
4
5x
S.P. of 2
nd
scooter = Rs. (18000−x)×
100
80
= Rs.
5
4
(18000−x)
Since Rohit neither gains nor loses, his total S.P. = Total C.P.
⇒
4
5x
+
5
4
(18000−x)=18000
⇒
4
5x
−
5
4x
=18000−14400=3600
⇒
20
25x−16x
=3600⇒9x=3600×20
⇒x=
9
3600×20
=8000
∴ C.P. of 1
st
scooter = Rs. 8000
C.P. of 2
nd
scooter = Rs. 10,000
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