Question

Rohit deposited 8000in a finance company for 3 years at an intrest of 12% per annum what is the compound interest that rohit gets after 3year
?​

Answer 1

$\frac{1+R}{100}$n

Given :

P= 8000

R= 12 % p.a

N= 3 years

Now :

8000$\frac{12}{100}3$

Answer = 8000.001728

Answer 2

Answer:

Principal (P) = ₹8000

Rate of Compound Interest (R) = 12%

Time (n) = 3 years

CI = P[ (1+R/100)ⁿ - 1]

= 8000 [ (1+12/100)³ - 1]

= 8000 [ (24/25)³ -1]

= 8000 [ (21952/15625) -1]

= 8000 [ (6327/15625]

= 3239.43 apx

Hope it works