rohit focused the image of a candle flame on a white screen using a convex lens . he noted down the position of the candle , screen and lens as under : position of candle :26.0 cm , position of convex lens : 50.0cm , positon of screen : 74.0 cm 1) what is the focal length of the convex lens? 2) where will the image be formed if he shifts the candle towards the lens at a position of 38cm? 3) draw a ray diagram to show the formation of the image in case ii) as said above?
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a long answer but I managed to type it
1) as the lens is convex, f can be found by using the formula f = uv/u+v cm, where u is the distance btwn the lens and candle and v is the distance btwn the lens and screen
u= 24cm
v= 24cm
f= 24*24/48= 12cm
2) after shifting, u= 12cm which means that u=f
so, the image will be at infinity
the ray diagram is posted as image.
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1) as the lens is convex, f can be found by using the formula f = uv/u+v cm, where u is the distance btwn the lens and candle and v is the distance btwn the lens and screen
u= 24cm
v= 24cm
f= 24*24/48= 12cm
2) after shifting, u= 12cm which means that u=f
so, the image will be at infinity
the ray diagram is posted as image.
plz mark as brainliest
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Answer:
( i ) . Object distance u = 50 - 26 = 24 cm
Image distance v = 74 - 50 = 24 cm .
Since object distance is equal to image distance.
2 f = 24
= > f = 12 cm
So , focal length of object is 12 cm.
( ii ) . u = 50 - 38 = 12 cm
It's mean candle is at focus.
= > Image will form at infinity.
( ii ) Refer to attachment for ray diagram.
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