Question

Rohit has Rs. 102.25 in the form of twenty five paise and fifty paise coins. If the number of twenty five paise coins is the square of 11, then the number of fifty paise coins is the square of which number?

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Answer 1

Answer:

7

Step-by-step explanation:

We know that Rohit has 102.25 rupees so, lets assume that number of 25 paise coin to be 'a'

And number of 50 paise coin to be 'b'

And given that a=square of 11

a=121 so the total amount of 25 paise is 25*121=3025 paise

That is 30.25 rupees

So the remaining rupees is the amount of coins of 50 paise so. Let the b coins contain c amount of rupees

So c=102.25-30.25

c=72

So from this b^2=72

==> b=6*1.414 (Since 1.414 is the value of root 2) SO FINALLY Ans is approximately 7