Math, asked by Rupman, 10 months ago

Rohit is twice old as Fahim . After twelve years their combined ages will be seven times Fahims age . What are their present ages​

Answers

Answered by sauravara101
7

Answer:

rohit's age=12

fahim's age=6

Step-by-step explanation:

Let rohit's and fahim's present ages be x and y respectively.

since, rohit is twice old as fahim.

so, x=2y

and, after 12 years ,

rohit's age =x+12

and, fahim's age =y+12

according to question,

x+12+y+12=7(y)

x+y+24=7y

3y+24=7y

4y = 24

y=6

and x=2y=2×6=12


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Answered by prettykohli
0

Answer:

Step-by-step explanation:

Step-by-step explanation:

Answer:

rohit's age=12

fahim's age=6

Step-by-step explanation:

Let rohit's and fahim's present ages be x and y respectively.

since, rohit is twice old as fahim.

so, x=2y

and, after 12 years ,

rohit's age =x+12

and, fahim's age =y+12

according to question,

x+12+y+12=7(y)

x+y+24=7y

3y+24=7y

4y = 24

y=6

and x=2y=2×6=12

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