Rohit places pencil perpendicular to principal axis in front of a converging mirror of length 30 cm the image formed is twice the size of the pencil calculate the distance of the object from the mirror
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yes,
so twice the size will be 30×2
then divide it by 5
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Answer:
Magnigfication = hi / ho = -v / u
We can assume it to be virtual because in a concave mirror, it is enlarged only when it is virtual. Otherwise, if you refer to the ray diagrams, they are all diminished.
The remaining procedure is correct, wherein we get -v /u = 2
So, if v = - 2u.
Using the mirror equation,
1 / v + 1 / u = 1 /f
= -1 / 2u + 1 / u = 1 / -30
u = - 15 cms. which is between the focal length and the mirror. This proves that the image will be virtual and enlarged.
Explanation:
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