Rohit's monthly expenditure is 20% more than Shivani's monthly income. Shivani's monthly expenditure is
20% less than the monthly income of Dhankar. Rohit's monthly expenditure is 50% more than that of
Dhankar's monthly income. If the monthly savings of Shivani is Rs. 7200. fmd the monthly income (in
rupees) of Shivani?
20000
15000
30000
25000
Answers
Answer:
20000
Step-by-step explanation:
try with the options. then you can solve this .
another way may be possible but I don't know.
so, please excuse me
Shivani's monthly income will be Rs.20000
Step-by-step explanation:
Given:
Rohit's monthly expenditure=20% more than Shivani's monthly income
Shivani's monthly expenditure=20%less than Dhankar's monthly income
Rohit's monthly expenditure=50% more than Dhankar's monthly income
Shivani's monthly savings=Rs.7200
To find:
Shivani's monthly income in (Rs.)
Solution:
Let's assume Shivani's monthly income as 100x & Dhankar's monthly income as 100y
According to condition 1
⇒Rohit's monthly expenditure=20% more than Shivani's monthly income
assuming Shivani's monthly income is 100x
∴ Rohit's monthly expenditure= 20% of 100x + 100x
=
Rohit's monthly expenditure= 20x+ 100x
∴ Rohit's monthly expenditure=120x.....................(1)
According to condition 2
Shivani's monthly expenditure=20% less than Dhankar's monthly income
assuming Dhankar's monthly income is 100y
∴ Shivani's monthly expenditure = 100y-20% of 100y
=
Shivani's monthly expenditure = 100y -20y
∴ Shivani's monthly expenditure = 80y......................(2)
As we know,
Savings= Income- Expenditure
∴ Shivani's monthly savings = Shivani's monthly income-(Shivani's monthly expenditure)
∴ 7200 = 100x- 80y....................[from given and (2)]
Dividing the equation by 20, we get
360= 5x+4y........................(3)
According to condition 3
Rohit's monthly expenditure=50% more than Dhankar's monthly income
assuming Dhankar's income is 100y
∴ Rohit's monthly expenditure= 50% of 100y + 100y
Rohit's monthly expenditure=
Rohit's monthly expenditure = 50y+100y
∴ Rohit's monthly expenditure= 150y...................(4)
Hence, from (1) and (4) we get
120x=150y
∴ 120x-150y=0
Dividing the equation by 30, we get
4x-5y=0.....................(5)
Now multiplying equation (3) by 5 & equation (5) by 4, we get
25x-20y=1800..........(6)
16x-20y=0..................(7)
Subtracting equation (7) from equation (6)
25x- 20y = 1800
16x- 20y = 0
(-) (+) (-)
9x = 1800................................(25x-16x=9x, -20y+20y=0, 1800-0=1800)
∴ x= 1800/9
∴ x=200
Thus, Shivani's monthly income=100x
=100(200)
∴ Shivani's monthly income= Rs 20000